The time the car and bus will meet if they leave at the same time, and one travels from Framingham to the airport while the other travels from the airport to Framingham is 12 minutes.
let
the distance between Logan airport and the town of Framingham = a
Car speed:
speed = distance / time
speed = a / 20
Logan express bus speed
speed = distance / time
speed = a / 30
let
the distance travelled by the car by the time they met = b
Then
the distance travelled by the bus the time they met = a - b
Therefore,
The time they met will be as follows:
speed = distance / time
time = distance / speed
b / a / 20 = a - b / a / 30
20b / a = 30(a - b) / a
cross multiply
20ab = 30(a - b)a
20ab = 30a²- 30ab
50ab = 30a²
5b = 3a
b = 3 / 5 a
Therefore,
b / a / 20 = 3 / 5 a / a / 20 = 3 / 5 a × 20 / a = 60a / 5a = 12 minutes
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