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Calculate the specific heat (J/g∘C) for a 13.5-g sample of zinc heated from 24.2 ∘C to 83.6 ∘C that absorbs 312 J of heat.

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Answer:

312j/13.5g×24.2°C+83.6°C

samueladesida43

The specific heat capacity of a 13.5-g sample of zinc heated from 24.2 ∘C to 83.6 ∘C that absorbs 312 J of heat is 0.389 J/g°C.

HOW TO CALCULATE SPECIFIC HEAT CAPACITY

The specific heat capacity of a substance can be calculated by using the following expression:

Q = mc∆T

Where;

  • Q = quantity of heat absorbed or released
  • m = mass of substance
  • c = specific heat capacity
  • ∆T = change in temperature

According to this question, a 13.5-g sample of zinc heated from 24.2∘C to 83.6 ∘C absorbs 312 J of heat. The specific heat is as follows:

312 = 13.5 × c × (83.6 - 24.2)

312 = 801.9c

c = 312 ÷ 801.9

c = 0.389

Therefore, the specific heat capacity of a 13.5-g sample of zinc heated from 24.2 ∘C to 83.6 ∘C that absorbs 312 J of heat is 0.389 J/g°C.

Learn more about specific heat capacity at: https://brainly.com/question/2530523

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