[tex]{\huge{\boxed{\mathbb{QUESTION}}[/tex]
[tex]\begin{bmatrix}5x-5y=-15\\ 3x-2y=-7\end{bmatrix}[/tex]
[tex]substitute\:x\:for\:-3+y[/tex]
[tex]\begin{bmatrix}3\left(-3+y\right)-2y=-7\end{bmatrix}[/tex]
[tex]{\huge{\boxed{\mathbb{SIMPLIFY}}[/tex]
[tex]\begin{bmatrix}-9+y=-7\end{bmatrix}[/tex]
add 9 to both sides
[tex]y=2[/tex]
Remember [tex]x=-3+y[/tex]
instead of [tex]y[/tex] we will put [tex]2[/tex]
[tex]x=-3+2\\x=-1[/tex]
[tex]{\huge{\boxed{\mathbb{ANSWER}}[/tex]
Answer:
( - 1 , 2 )
Step-by-step explanation:
5x - 5y = - 15
3x - 2y = - 7
[tex]\left \{ {{5x-5y=-15} \atop {3x-2y=-7}} \right.[/tex] ⇔ [tex]\left \{ {{x-y=-3} \atop {3x-2y=-7}} \right.[/tex] ⇔ [tex]\left \{ {{-3x+3y=9} \atop {3x-2y=-7}} \right.[/tex]
(1) + (2)
y = 2 -------> (1)
x = - 1
( - 1 , 2 )
