How many moles of the excess reagent would there be if 2.8mol of N2 were reacted with 15.1mol of H2O?

N2+4H2O ---> 2H2O2+N2H4

Respuesta :

The number of moles of the excess reagent there would be is 3.9 moles

From the question,

We are to determine the number of moles of the excess reagent there would be.

The given balanced chemical equation is

N₂ + 4H₂O → 2H₂O₂ + N₂H₄

This means,

1 mole of N₂ is required to react completely with 4 moles of H₂O

Now,

If 1 mole of N₂ is required to react completely with 4 moles of H₂O

Then,

2.8 moles of N₂ will react completely with 11.2 moles of H₂O

∴ H₂O is the excess reagent

Number of moles of H₂O that would remain = 15.1 mol - 11.2 mol

Number of moles of H₂O that would remain = 3.9 mol

Hence, the number of moles of the excess reagent there would be is 3.9 moles

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