Step-by-step explanation:
Since you can't directly solve for [tex]y[/tex] in this question, we will use substitution to solve for
[tex]{\large{\boxed{\mathbb{QUESTION}}}[/tex]
What would y equal in this equation?
[tex]\begin{bmatrix}3+\frac{4}{1}y=5\\ x+2=0\end{bmatrix}[/tex]
[tex]{\large{\boxed{\mathbb{SOLVE\:FOR\:Y}}}[/tex]
[tex]3+\frac{4}{1}y=5[/tex]
First, we will subtract 3 from both sides of the equation
[tex]\frac{4}{1}y=2[/tex]
Simplify
[tex]{4}y=2[/tex]
Divide both sides by 4
[tex]y=\frac{1}{2}[/tex]
[tex]{\large{\boxed{\mathbb{SOLVE\:FOR\:X}}}[/tex]
[tex]x+2=0[/tex]
subtract 2 to both sides
[tex]x=-2[/tex]
[tex]{\large{\boxed{\mathbb{ANSWER}}[/tex]
_____________________________________
If we didn't use the method with substitution and had our equation being
[tex]3+\frac{4}{1y}=5x+2[/tex]
our answer would've been
[tex]y=\frac{-4}{-5x+1}[/tex], I highly doubt this would be the right answer.
