Answer:
[tex]\log _8\left(\frac{1}{8}\right)=-1[/tex]
Step-by-step explanation:
[tex]{\huge{\boxed{\mathbb{QUESTION}}}[/tex]
Write the equation in logarithmic form.
[tex]8^{-1}=\frac{1}{8}[/tex]
Definition of logarithmic form
⇒[tex]a^n=b\quad \Rightarrow \quad \log _ab=n[/tex]
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- [tex]a=8[/tex]
- [tex]b=\frac{1}{8}[/tex]
- [tex]n=-1[/tex]
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Plug in the values
[tex]8^{-1}=\frac{1}{8} \quad \Rightarrow \quad \log _8\frac{1}{8} =-1[/tex]
[tex]{\huge{\boxed{\mathbb{ANSWER}}}[/tex]
[tex]\quad \log _8(\frac{1}{8}) =-1[/tex]
