A sample of methane gas, CH4, occupies a volume (L) of 58.2 L at a pressure of 7.25 atm. What volume will the gas occupy if the pressure is lowered to 2.03 atm?

Respuesta :

Taking into account the Boyle's law, the gas will ocuppy a volume of 207.86 L.

Boyle's law is one of the gas laws that relates the volume and pressure of a certain quantity of gas kept at a constant temperature.

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant.

Mathematically, Boyle's law states that the product of pressure and volume is constant:

P×V= k

Studying two different states, an initial state 1 and a final state 2, it is satisfied:

P1× V1= P2× V2

In this case, you know:

  • P1= 7.25 atm
  • V1= 58.2 L
  • P2= 2.03 atm
  • V2= ?

Replacing in Boyle's law:

7.25 atm× 58.2 L= 2.03 atm× V2

Solving:

V2= (7.25 atm× 58.2 L)÷ 2.03 atm

V2= 207.86 L

In summary, the gas will ocuppy a volume of 207.86 L.

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