contestada

The temperature of an object increases by 26.1 °C when it absorbs 3711 J of heat. Calculate the heat capacity of the object.

C = ________________ J/°C

Respuesta :

Answer:

[tex]\displaystyle C = 142\text{ } \frac{J}{^\circ C}[/tex]

Explanation:

We can utilize the heat capacity formula:

[tex]\displaystyle q = C\Delta T[/tex]

Where q is the heat energy, C is its heat capacity, and ΔT is the change in temperature.

By substitution, q = 3711 J and ΔT = 26.1 °C. Hence:

[tex]\displaystyle \begin{aligned} (3711 \text{ J}) & = C(26.1\text{ } ^\circ\text{C}) \\ \\ C & = 142\text{ } \frac{J}{^\circ C}\end{aligned}[/tex]

Hence, the heat capacity of the substance is about 142 J per degrees Celsius.