What is an equation of the line that passes through the points (-6,3) and (-5,2)

Slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept
Point-slope form, which is [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1, y_1)[/tex] is a point
Standard form, which is ax+by=c, where a, b, and c are free integer coefficients, but a and b cannot be equal to zero, and a cannot be negative

The most common way to write the equation of the line is in slope-intercept form, so let's do it that way.

First, we'll need to find the slope of the line

The formula for the slope calculated from 2 points is [tex]\frac{y_2-y_1}{x_2-x_1}[/tex], where [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] are points

Although we already have 2 points, let's label their values in order to avoid confusion later:

[tex]x_1= -6\\y_1=3\\x_2=-5\\y_2=2[/tex]

Now substitute these values into the formula to find slope (m):

m=[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

Substitute (remember: we have NEGATIVE numbers, but the formula calls for SUBTRACTION, so we'll end up subtracting a negative):

m=[tex]\frac{2-3}{-5--6}[/tex]

Simplify:

m=[tex]\frac{2-3}{-5+6}[/tex]

Add/subtract the numbers together:

m=[tex]\frac{-1}{1}[/tex]

Divide

m=-1

We can substitute this as m in y=mx+b:

y=-1x+b, or y=-x+b

We need to find b now

Since the equation passes through both (-6, 3) and (-5, 2), we can use either point to solve for b

Taking (-6, 3) for example:

Substitute -6 as x and 3 as y

3=-1(-6)+b

Multiply

3=6+b

Subtract 6 from both sides

-3=b

Substitute -3 as b into the equation

y=-x-3

Hope this helps!