Answer:
Step-by-step explanation:
Let x = base side length
y = side height
volume V = x²y
y = V/x²
surface area
A = x² + 4xy
A = x² + 4x(V/x²)
A = x² + 4V/x
Solving for volume
V = (A - x²)(x/4)
V = ¼(Ax - x³)
a maximum will occur when the derivative equals zero
V' = ¼(A - 3x²)
0 = ¼(A - 3x²)
0 = A - 3x²
3x² = A
3x² = 1100
x² = (1100 / 3)
x = √(1100/3)
V = (A - x²)(x/4)
V = (1100 - √(1100/3))²(√(1100/3)/4)
V = 3,510.56606...
V = 3510.6 cm³
The box height will be half of the base side length.
y = ½√(1100/3)