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A 15-volt power supply is used to power a circuit with two resistors in series. The voltage drop across R1 is 5 volts. What is the voltage drop across R2?

5 volts

20 volts

10 volts

0 volts



A 10-volt power supply is used to power a circuit, producing a current of 2 A. If total resistance of circuit is doubled, how will this affect the circuit?

A. Voltage drop across each resistor will all double to match change in resistance

B. The current will change so that the voltage drop for a complete loop through the circuit becomes 5 V.

C. The current will change so that the voltage drop for a complete loop through the current remains at 10 V.

D. The voltage drop across each resistor will be unaffected because each will remain at 0 V

Respuesta :

onyebuchinnaji

(1) The voltage drop in the second resistor is 10 V.

(2) The voltage drop across each resistor will all double to match change in resistance.

The given parameters:

  • voltage in the circuit, V = 15 V
  • voltage drop in first resistor, V1 = 5 V

The total voltage in a series circuit is given as;

[tex]V_T = IR_1 + IR_2\\\\V_T = V_1 + V_2[/tex]

The voltage drop in the second resistor is calculated as follows;

[tex]V_2 = V_T - V_1\\\\V_2 = 15 - 5\\\\V_2 = 10 \ V[/tex]

(2)

  • voltage supply, V = 10 V
  • current, I = 2 A

The resistance of the circuit:

[tex]R = \frac{V}{I} = \frac{10}{2} = 5 \ ohms[/tex]

When the total resistance is doubled;

In series circuit, the current in each resistor is constant, the voltage drop is calculated as;

[tex]V = IR\\\\V = 2 (5+5)\\\\V = 20 \ V[/tex]

Thus, we can conclude that the voltage drop across each resistor will all double to match change in resistance.

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