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A 10 kg box is motionless on the floor. If the coefficient of static friction is 0.4 and
the coefficient of kinetic friction is 0.3 (between the box and the floor), find the
force required to start the block in motion

Respuesta :

onyebuchinnaji

The force required to start the given box in motion is 39.2 N.

The given parameters;

  • mass of the box, m = 10 kg
  • coefficient of static friction, [tex]\mu_s[/tex] = 0.4
  • coefficient of kinetic friction [tex]\mu_k[/tex] =  0.3

The force required to start the box in motion must be greater or equal to static frictional force.

The magnitude of the force is calculated as follows;

[tex]F = \mu_s F_n\\\\F = \mu_s mg\\\\F = (0.4) \times (10) \times (9.8)\\\\ F = 39.2 \ N[/tex]

Thus, the force required to start the box in motion is 39.2 N.

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