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What are the domain and range of f(x) = (one-sixth) Superscript x + 2?

domain: Left-brace x vertical-line x greater-than negative one-sixth right-brace; range: {y | y > 0}
domain: Left-brace x vertical-line x greater-than one-sixth right-brace; range: {y | y > 2}
domain: {x | x is a real number}; range: {y | y > 2}
domain: {x | x is a real number}; range: {y | y > –2}

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abidemiokin

The domain and range of the function is domain: {x | x is a real number}; range: {y | y > 2}

Given the exponential function expressed as;

[tex]f(x)=(\frac{1}{6})^x + 2[/tex]

The domain of the function will be the input value "x" for which it exists. For the function given, it exists for any value of "x".

  • Hence the domain of the function exists on all real numbers. Hence the domain in set notation is domain: {x | x is a real number}

  • The range of the function will be the output value "f(x)" for which it exists. For the function given, it exists for any value of f(x) greater than 2.

  • Hence the range of the function exists on any value of f(x) greater than 2. Hence the range in set notation is domain: {y | y >2}

Learn more here: https://brainly.com/question/24041834

Answer:

The answer is C on edge

Step-by-step explanation:

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