The coefficient of the frictional force on the block is 0.102.
The given parameters;
- mass of the block, m = 7 kg
- force applied, F = 7 N
The normal force on the block is calculated as follows;
[tex]F_n = mg\\\\F_n = 7 \times 9.8\\\\F_n = 68.6 \ N[/tex]
The frictional force on the block is calculated as;
[tex]F_f = \mu F_n\\\\F_f = 68.6 \mu[/tex]
The net horizontal force on the block is calculated as;
[tex]\Sigma F = 0\\\\F - F_f = 0\\\\F_f = F\\\\68.6 \mu = 7\\\\\mu = \frac{7}{68.6} \\\\\mu = 0.102[/tex]
Thus, the coefficient of the frictional force on the block is 0.102.
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