Answer:
y = [tex]\frac{x^{2} + 27}{8}[/tex]
Step-by-step explanation:
To find the inverse, we will set it equal to y, switch the x and y values, then solve for y.
[Given] h(x)=3 square root x -3
[Rewrite] y = 3 [tex]\sqrt{x-3}[/tex]
[Switch values] x = 3 [tex]\sqrt{y-3}[/tex]
[Square both sides] x² = 9(y - 3)
[Distrubte] x² = 8y - 27
[Add 27 to both sides & flip equation] 8y = x² + 27
[Divide both sides of 8] y = [tex]\frac{x^{2} + 27}{8}[/tex]
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
