The work done by the given force at the given displacement is [tex](1812 \times d )\ J[/tex].
The given parameters;
- applied force, F = 2000 N
- angle between the force and the displacement, θ = 25⁰
Let the displacement = d
The work done by the given force at the given displacement is calculated as follows;
[tex]W = Fd \times cos(\theta)\\\\W = 2000 \times d \times cos(25)\\\\W = (1812\times \ d) \ J[/tex]
Thus, the work done by the given force at the given displacement is [tex](1812 \times d )\ J[/tex].
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