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A random number generator assigned each pepper to one of two groups. The weights of the peppers in each group, given three randomizations, appear in the tables.

First randomization
group a
13.6
12.1
15.9
11.2
9.7
group b
9.2
8.2
11.5
13.8
14.6

A random number generator assigned each pepper to one of two groups The weights of the peppers in each group given three randomizations appear in the tables Fir class=

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Using the formula for the mean, it is found that:

  • 1. After the first randomization, [tex]\mu_A[/tex] is 12.5, [tex]\mu_B[/tex] is 11.46 and [tex]\mu_A - \mu_B[/tex] is 1.04.
  • 2. After the second randomization, [tex]\mu_A[/tex] is 11.36, [tex]\mu_B[/tex] is 12.6 and [tex]\mu_A - \mu_B[/tex] is -1.24.
  • 3. After the third randomization, [tex]\mu_A[/tex] is 11.98, [tex]\mu_B[/tex] is 11.98 and [tex]\mu_A - \mu_B[/tex] is 0.

The mean of a data-set is the sum of all observations divided by the number of observations.

  • When two variables are subtracted, the mean is the subtraction of the means.
  • In this problem, each randomization is composed of two sets of 5 observations.

For the first randomization:

[tex]\mu_A = \frac{13.6 + 12.1 + 15.9 + 11.2 + 9.7}{5} = 12.5[/tex]

[tex]\mu_B = \frac{9.2 + 8.2 + 11.5 + 13.8 + 14.6}{5} = 11.46[/tex]

[tex]\mu_A - \mu_B = 12.5 - 11.46 = 1.04[/tex]

1. After the first randomization, [tex]\mu_A[/tex] is 12.5, [tex]\mu_B[/tex] is 11.46 and [tex]\mu_A - \mu_B[/tex] is 1.04.

For the second randomization:

[tex]\mu_A = \frac{8.2 + 13.8 + 15.9 + 9.2 + 9.7}{5} = 11.36[/tex]

[tex]\mu_B = \frac{12.1 + 14.6 + 13.6 + 11.2 + 11.5}{5} = 12.6[/tex]

[tex]\mu_A - \mu_B = 11.36 - 12.6 = -1.24[/tex]

2. After the second randomization, [tex]\mu_A[/tex] is 11.36, [tex]\mu_B[/tex] is 12.6 and [tex]\mu_A - \mu_B[/tex] is -1.24.

For the third randomization:

[tex]\mu_A = \frac{8.2 + 9.7 + 11.5 + 14.6 + 15.9}{5} = 11.98[/tex]

[tex]\mu_B = \frac{12.1 + 13.8 + 13.6 + 11.2 + 9.2}{5} = 11.98[/tex]

[tex]\mu_A - \mu_B = 11.98 - 11.98 = 0[/tex]

3. After the third randomization, [tex]\mu_A[/tex] is 11.98, [tex]\mu_B[/tex] is 11.98 and [tex]\mu_A - \mu_B[/tex] is 0.

A similar problem is given at https://brainly.com/question/22056321

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