[tex] \huge ༆ \bf{Answer} ༄[/tex]
The liquid that the cone can store is its volume, So let's calculate the volume of cone
It is given by : -
- [tex] \sf \: v = \dfrac{1}{3} \pi {r}^{2} h[/tex]
radius = diameter ÷ 2 = 3 ÷ 2 = 1.5 in
height = 4 inches
- [tex] \sf \: v = \dfrac{1}{3} \pi \times 1.5 \times 1.5 \times 4[/tex]
- [tex] \sf \: v = \pi \times 1.5 \times 2[/tex]
- [tex] \sf \: v = 3\pi \: \: in {}^{3} [/tex]
The liquid that the cone can hold without overflowing is 3π in³
[tex]꧁ \: \frak{Eternal \: Being } \: ꧂[/tex]
