A 15 kg piece of furniture slides down a ramp 5.4 m long. The incline of the ramp is 32 degrees above the horizontal. The friction force acting during the journey is 25.4 N. What is the resulting work?

Respuesta :

The resulting work done by the frictional force on the moving furniture is 116.32 J.

The given parameters;

  • mass of the furniture, m = 15 kg
  • length of the ramp, L = 5.4 m
  • inclination of the ramp, θ = 32⁰
  • frictional force on the furniture, [tex]F_f[/tex] = 25.4 N

The resulting work done by the frictional force on the moving furniture is calculated as follows;

[tex]W = F_f \times l \times cos(\theta)\\\\W = 25.4 \times 5.4 \times cos(32)\\\\W = 116.3 2 \ J[/tex]

Thus, the resulting work done by the frictional force on the moving furniture is 116.32 J.

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