PLZ HELP DUE SOOOONNNN (solve for z).

Answer:
[tex]{\huge{\green{\mathsf{z\:=\sqrt{\frac{4x}{3y}}}}}[/tex]
Step-by-step explanation:
Given the algebraic equation, [tex]{\huge{\green{\mathsf{x\:=\frac{3yz^2}{4}}}}[/tex], and that we must solve for z :
The first step is to multiply both sides by 4 to eliminate the fraction on the right-hand side of the equation:
[tex]{\huge{\green{\mathsf{x\:=\frac{3yz^2}{4}}}}[/tex]
[tex]{\huge{\green{\mathsf{(4)\:x\:=\frac{3yz^2}{4}(4)}}}[/tex]
4x = 3yz²
Next, divide both sides by 3y:
[tex]{\huge{\green{\mathsf{\frac{4x}{3y}\:=\frac{3yz^2}{3y}}}}[/tex]
[tex]{\huge{\green{\mathsf{\frac{4x}{3y}\:=z^2}}}[/tex]
Lastly, take the square root of both sides to isolate the variable, z :
[tex]{\huge{\green{\mathsf{\sqrt{\frac{4x}{3y}}\:=\sqrt{z^2}}}}[/tex]
[tex]{\huge{\green{\mathsf{z\:=\sqrt{\frac{4x}{3y}}}}}[/tex]
Therefore, the equation for z is: [tex]{\huge{\green{\mathsf{z\:=\sqrt{\frac{4x}{3y}}}}}[/tex]
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