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According to sales records at a local coffee shop, 75% of all customers like hot coffee, 30% like iced coffee, and 22% like both hot and iced coffee. The Venn diagram displays the coffee preferences of the customers.​

According to sales records at a local coffee shop 75 of all customers like hot coffee 30 like iced coffee and 22 like both hot and iced coffee The Venn diagram class=

Respuesta :

Using Venn probabilities, it is found that there is a 0.08 = 8% probability that the customer only likes iced coffee.

In this problem, the events are:

  • Event H: Liking hot coffee.
  • Event I: Liking iced coffee.

The probability of only liking iced coffee is:

[tex]P(I \cap H^c) = P(I) - P(I \cap H)[/tex]

  • 30% like iced coffee, hence [tex]P(I) = 0.3[/tex].
  • 22% like both hot and iced coffee, hence [tex]P(I \cap H) = 0.22[/tex]

Then:

[tex]P(I \cap H^c) = P(I) - P(I \cap H) = 0.3 - 0.22 = 0.08[/tex]

0.08 = 8% probability that the customer only likes iced coffee.

A similar problem is given at https://brainly.com/question/24707032

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