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a. A pure sample was analysed and was found to contain 6.25 g of lithium, 5.40 g of carbon, & 21.60
g of oxygen. Calculate the empirical formula. Show your work out. If you do not show any work out,
marks will not be given. [3]
b. The molar mass of the compound is 116 g/mol, what is its molecular formula?

PLS URGENTLY ANS

Respuesta :

The empirical formula of the compound is Li₂CO₃

First, we will determine the respective number of moles of each element present in the compound by dividing by their atomic masses

Lithium                      Carbon                          Oxygen

6.25÷6.94                 5.40÷12.01                    21.60÷16.00

0.9006                      0.4496                          1.35

Now, divide through by the smallest number of moles, that is, 0.4496

Lithium                      Carbon                          Oxygen

0.9006÷0.4496        0.4496÷0.4496            1.35÷0.4496

2                                      1                                    3

Hence, the empirical formula of the compound is Li₂CO₃

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