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A 10 kg box is motionless on the floor. If the coefficient of static friction is 0.4 and the coefficient of kinetic friction is 0.3 (between the box and the floor), find the force required to start the block in motion
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Lanuel

The force required to start the block in motion is equal to 39.2 Newton.

Given the following data:

  • Mass of box = 10 kg
  • Coefficient of static friction = 0.4
  • Coefficient of kinetic friction = 0.3

To determine the force required to start the block in motion:

Note: The force that is required to start the block in motion must be greater than or equal to the force of static friction.

Mathematically, the force of static friction is given by the formula;

[tex]Fs = uFn = umg[/tex]

Where;

  • Fs represents the force of static friction.
  • μ represents the coefficient of friction.
  • [tex]F_n[/tex] represents the normal force.
  • g is the acceleration due to gravity.
  • m is the mass of an object.

Substituting the given parameters into the formula, we have;

[tex]F_s = 0.4 \times 10 \times 9.8\\\\F_s = 4 \times 9.8\\\\F_s = 39.2\;Newton[/tex]

Read more on force of static friction here: https://brainly.com/question/25686958

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