Respuesta :

  • P_1=1atm
  • V_1=500ml
  • V_2=600ml
  • P_2=?

Using Boyle's law

[tex]\\ \sf\longmapsto P\propto \dfrac{1}{V}[/tex]

[tex]\\ \sf\longmapsto \dfrac{P_1}{P_2}=\dfrac{V_2}{V_1}[/tex]

[tex]\\ \sf\longmapsto \dfrac{1}{P_2}=\dfrac{600}{500}[/tex]

[tex]\\ \sf\longmapsto P_2=\dfrac{5}{6}[/tex]

[tex]\\ \sf\longmapsto P_2=633.3mmHg[/tex]

  • H=760-633.3=126.67m

Based on the information given, it should be noted that the height will be 126.67m.

Solving the height

From the information given, the pressure and the volume have been given. Therefore, the height will be calculated thus:

1/P = 600/500

P = 500/600.

P = 633.3mmHg

Therefore, height will be:

= 760 - 633.30

= 126.67

Learn more about heights on:

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