The area of the skywalk floor is the amount of space it occupies
The area of the skywalk floor is 1728.1 square feet
From the complete question, we have the following parameters
The outer diameter is 65 feet
This is represented as: [tex]\mathbf{d_2 = 65}[/tex]
The inner diameter is calculated as follows:
[tex]\mathbf{d_1 = 65 - 2 * 10}[/tex]
[tex]\mathbf{d_1 = 45}[/tex]
So, the area of the skywalk floor is the difference between the areas of the two semicircles.
This is represented as:
[tex]\mathbf{Area = \frac{\pi d_2^2}{4} - \frac{\pi d_1^2}{4}}[/tex]
Rewrite as:
[tex]\mathbf{Area = \frac{\pi}{4}(d_2^2 - d_1^2)}[/tex]
So, we have:
[tex]\mathbf{Area = \frac{3.142}{4}(65^2 - 45^2)}[/tex]
[tex]\mathbf{Area = \frac{3.142}{4}(2200)}[/tex]
Simplify
[tex]\mathbf{Area = 3.142 \times 550}[/tex]
[tex]\mathbf{Area = 1728.1}[/tex]
Hence, the area of the skywalk floor is 1728.1 square feet
Read more about areas at:
https://brainly.com/question/20898622
