The equation of the parabola whose focus is (-2,2) and whose directrix is x= -8 is [tex](y+2)^2=-20(x+5)[/tex]
The standard formula for finding an equation of a parabola is expressed as [tex]y^2=4ax[/tex]
If the curve is shifted to the left and down, the equation becomes [tex](y-k)^2=4a(x-h)[/tex] where:
(h, k) is the vertex of the parabola
If the focus is at (-2, 2) and the directrix is at x = -8, the equivalent vertex of the parabola will be at (-5, -2) and the midpoint between the vertex and directrix is at a = -5
Substitute these values into the formula of the parabola.
[tex](y-k)^2=4a(x-h)\\(y-(-2))^2=4(-5)(x-(-5))\\(y+2)^2=-20(x+5)\\[/tex]
Hence the equation of the parabola whose focus is (-2,2) and whose directrix is x = -8 is [tex](y+2)^2=-20(x+5)[/tex]
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