Answer:
y=2x+8
Step-by-step explanation:
Hi there!
We want to find the equation of the line that passes through the points (-6, -4) and (-4, 0).
There are 3 ways to write the equation of the line:
Let's write the equation in slope-intercept form, which is the most common way to do it.
We'll need to start by finding the slope of the line
The formula for the slope calculated from two points is [tex]\frac{y_2- y_1}{x_2-x_1}[/tex], where [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] are points
Even though we are already given two points, let's label their values in order to avoid any confusion and mistakes for later:
[tex]x_1=-6\\y_1=-4\\x_2=-4\\y_2=0[/tex]
Substitute these equations into the formula to find the slope (m):
m=[tex]\frac{y_2- y_1}{x_2-x_1}[/tex]
Substitute (remember: we have NEGATIVE numbers and SUBTRACTION, so we'll end up subtracting a negative):
m=[tex]\frac{0- -4}{-4--6}[/tex]
Simplify
m=[tex]\frac{0+4}{-4+6}[/tex]
Add the numbers together
m=[tex]\frac{4}{2}[/tex]
Divide
m=2
The slope of the line is 2
We can immediately plug it into the formula for slope-intercept form as m:
y=2x+b
Now we need to find b
As the equation passes through both (-6, -4) and (-4, 0), we can use either one of them to solve for b
Taking (-4, 0) for example:
Substitute -4 as x and 0 as y:
0=2(-4)+b
Multiply
0=-8+b
Add 8 to both sides
8=b
Substitute 8 as b into the equation
y=2x+8
Hope this helps!
