Newton's second law allows to find the acceleration of the two-body system, where a mass is hanging is:
Newton's second law states that the net force on a body is equal to the product of the mass and the acceleration.
∑ F = m a
Where the bold letters indicate vectors, F is the force, m the mass and the acceleration of the body.
A free body diagram is that diagram of the system where the forces are shown without the details of the bodies. In the attachment we have a free-body diagram of the system.
Let's write Newton's second law for each axis.
x- axis
T = m₁ a
y-axis
body in the horizontal part
N-W₁ = 0
N = W₁
Body hanging.
W₂ - T = m₂ a
Wwhere the positive direction is down, let's write our system of equations.
T = m₁ a
W₂-T = m₂ a
Let's Resolve.
m₂ g = (m₁ + m₂) a
a = [tex]\frac{m_2}{m_1+m_2} \ g[/tex]
Let's calculate.
a =[tex]\frac{63}{10+63} \ 9.8[/tex]
a = 8.46 m / s²
In conclusion using Newton's second law we can find the acceleration of the two-body system, where a mass is hanging is:
Learn more about Newton's second law here: brainly.com/question/13959891
