The confidence interval is between (48.2%, 57.7%)
Using the proportion formula expressed as:
[tex]CI=p\pm z\cdot \sqrt{\frac{p(1-p)}{n} }[/tex]
Get the proportion:
p = 320/600 = 0.53
[tex]z=\frac{x- \mu}{\sigma}[/tex]
[tex]z = \frac{320-240}{47}\\z=\frac{80}{47}\\z= 1.70[/tex]
Substitute into the formula to get the confidence interval to have:
[tex]CI=0.53\pm 1.7\cdot \sqrt{\frac{0.47}{600}}\\CI = 0.53\pm 0.04757\\CI = (0.53-0.04757, 0.53+0.04757)\\CI = (0.482, 0.577)[/tex]
Hence the confidence interval is between (48.2%, 57.7%)
Learn more on confidence interval here: https://brainly.com/question/20066592
