help me
[tex] \: [/tex]

if mCE =100° ,mCA =110° and CR is a diameter find

mAR
mER

ANSWER 6-10 PLSS
see the attachment plss
need properly answer
right answer get brainlist
nonsense answer will be reported
[tex] \: [/tex]

help metex texif mCE 100 mCA 110 and CR is a diameter find mARmERANSWER 610 PLSSsee the attachment plssneed properly answerright answer get brainlist nonsense a class=

Respuesta :

Step-by-step explanation:

#6

  • mAR = mCR - mCA = 180° - 110° = 70°

#7

  • mER = mCR - mCE = 180° - 100° = 80°

#8

  • m∠CAR = 90° as CR is diameter

#9

  • m∠CRA = 1/2(mCA) = 1/2(110°) = 55°

#10

  • m∠ROE = m∠COR - m∠COE = 180° - 100° = 80°