Write a class number which has Following
N - integer
Methods
Default constructor
Argument constructor
setN method to change the value of N
isprime() to check that N is a prime number isarmstrong to check N is Armstrong iseven() to check if N is even or odd these method should also work for given numbers
class should have provision to know the count of objects

A class attribute called count_instances that is incremented anytime an instance is created. Thus, it keeps count of the number of instances created.

An instance attribute called N that stores the number

Python does not allow operator overloading by default. To implement default and argument constructors, use default/optional arguments. Though there are other ways, this is the simplest approach for the purposes of this problem.

The isPrime method checks if the constructed number is a prime number. The for loop runs from 2(since this is the first prime number) to int(sqrt(N)), and checks which of these numbers divides N. If none divides N, then N is prime, and it returns true, else it returns false.

isArmstrong checks if the number is an Armstrong number. To easily get the order of the number, the number is converted to a string and the number of characters is gotten.

The number is an Armstrong Number if

[tex]abc...=a^n+b^n+c^n+...[/tex]

where

[tex]n=\text{order of the number, or, number of digits in the number}\\a,b,c,...=\text{the individual digits of the number}[/tex]

See another example on Prime numbers here: https://brainly.com/question/20379340