meme200911
contestada

A man applies a force of 540 N to the barrow in a direction 75 from the horizontal. He moves the barrow 30 m along the level ground. Calculate the work he does against friction? ​

Respuesta :

onyebuchinnaji

The work done by the man against friction is 4,192.86 J.

The given parameters;

  • force applied, F = 540 N
  • angle of inclination, θ = 75⁰
  • horizontal distance, x = 30 m

The work done by the man against friction is calculated as follows;

[tex]W = F \times d \times cos(75)\\\\W = 540 \times 30 \times cos(75)\\\\W = 4,192.86 \ J[/tex]

Thus, the work done by the man against friction is 4,192.86 J.

Learn more here:https://brainly.com/question/19498865

Otras preguntas