The completed proof is presented as follows;
By definition of a rhombus [tex]\overline{JK} \cong \overline{KM}[/tex] and by the reflexive property of
congruence [tex]\overline{KP} \cong \overline{KP}[/tex], because the diagonals of a rhombus bisect a pair
of opposite angles, ∠JKP ≅ ∠MKP, making ΔJKP ≅ ΔMKP by the SAS
congruency postulate, because CPCTC, ∠JPK ≅ ∠MPK, and these angles
are right angles because two angles that form a linear pair are congruent,
thereby making, [tex]\overline{JK} \perp \overline{KM}[/tex] by definition of perpendicular segments.
Reasons:
Please find attached the drawing of the given rhombus JKMH, that show
the point of intersection of the diagonals JM and HK at point P.
Learn more about the properties of a rhombus here:
https://brainly.com/question/10618409