The percentage by mass of the acetic acid is 0.057%.
The given parameters:
The concentration of the acetic acid is calculated as follows;
[tex]C_1V_1 = C_2 V_2\\\\C_1 = \frac{ C_2 V_2}{V_1} \\\\C_1 = \frac{0.01 \times 250}{10} \\\\C_1 = 0.25 \ M[/tex]
The number of moles of acetic acid in the given concentration;
[tex]C = \frac{mol}{L} \\\\mole = CL\\\\mole = 0.25 \times 10 \times 10^{-3} \\\\mole = 0.0025[/tex]
The molar mass of acetic acid = 60 g/mol
The mass of acetic acid in the given number of moles is calculated as follows;
m = conc. x molar mass
m = 0.0025 x 60
m = 0.15 g
The mass of vinegar in the volume and density;
m = density x volume
m = 1.05 x 250
m = 262.5 g
The percentage by mass of the acetic acid is calculated as follows;
[tex]= \frac{0.15}{262.5} \times 100\%\\\\= 0.057 \%[/tex]
Thus, the percentage by mass of the acetic acid is 0.057%.
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