The reactant that has been present in excess in the reaction has been NaCl. Thus, option B is correct.
The balanced chemical equation has been:
[tex]\rm NaCl\;+\;AgNO_3\;\rightarrow\;NaNO_3\;+\;3\;AgCl[/tex]
From the balanced equation, for complete utilization of 1 mole of sodium chloride, 1 mole of silver nitrate has been used.
The moles of can be given as:
[tex]\text Moles\;=\;\dfrac{m}{mwt}[/tex]
Where, mass of Silver nitrate, [tex]m=10\;\text g[/tex]
Molecular mass of silver nitrate, [tex]mwt=168\9.87\;\text {g/mol}[/tex]
Substituting the values, moles of silver nitrate has been:
[tex]\rm Moles \;AgNO_3=\dfrac{10}{169.87} \\Moles \;AgNO_3=0.058\;mol[/tex]
Mass of sodium chloride, [tex]m=4\;\text g[/tex]
Molecular mass of sodium chloride, [tex]mwt=58.44\;\text {g/mol}[/tex]
Substituting the values, moles of sodium chloride has been:
[tex]\rm Moles\;NaCl=\dfrac{4}{58.44}\\Moles\;NaCl=0.068\;mol[/tex]
From the balanced chemical equation,
[tex]\rm 1\;moles\;AgNO_3=1\;moles\;NaCl\\0.058\;mol\;AgNO_3=0.058\;mol\;NaCl[/tex]
Since, the available moles of NaCl has been 0.06 mol, and used NaCl has been 0.05 mol. Thus, NaCl has been the excess reactant. Hence, option B is correct.
For more information about the excess reactant, refer to the link:
https://brainly.com/question/25685654
Answer:
B- NaCl
Explanation:
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