Find: (4x2y3 2xy2 â€"" 2y) â€"" (â€""7x2y3 6xy2 â€"" 2y) Place the correct coefficients in the difference. X2y3 xy2 y.

Respuesta :

The required coefficient is 11,-4 and 0.

Given expression is,

[tex](4x^2y^3 + 2xy^2- 2y) -(-7x^2y^3 + 6xy^2-2y)[/tex]

we have to find the coefficient of the above expression.

ON solving the above expression,

[tex](4x^2y^3 + 2xy^2- 2y) -(-7x^2y^3 + 6xy^2-2y)=4x^{2} y^{3} +2xy^2-2y+7x^2y^3-6xy^2+2y[/tex]

[tex](4x^2y^3 + 2xy^2- 2y) -(-7x^2y^3 + 6xy^2-2y)=11x^2y^3-4xy^2+0y[/tex]

Hence from the above expression, it is clear that the coefficient of [tex]x^2y^3[/tex] is 11,[tex]xy^2[/tex] is -4 and [tex]y[/tex] is 0.

For more details on coefficient follow the link:

https://brainly.com/question/10702726