A simple random sample of 85 is drawn from a normally distributed population, and the mean is found to be 146, with a standard deviation of 34. Which of the following values is outside the 99% confidence interval for the population mean? Use the table below to help you answer the question. Confidence Level 90% 95% 99% z*-score 1. 645 1. 96 2. 58 Remember, the margin of error, ME, can be determined using the formula M E = StartFraction z times s Over StartRoot n EndRoot EndFraction. The value of 135 because it is not greater than 136. 5 the value of 137 because it is greater than 136. 5 the value of 138 because it is less than 153. 2 the value of 154 because it is greater than 153. 2.

Respuesta :

The correct option is ''The value of 135 because it is not greater than 136.5 values is outside the 99% confidence interval for the population mean''

Given that,

A simple random sample of 85 is drawn from a normally distributed population, and the mean is found to be 146, with a standard deviation of 34.

We have to find,

Which of the following values is outside the 99% confidence interval for the population mean?

According to the question,

A simple random sample of 85 is drawn from a normally distributed population, and the mean is found to be 146, with a standard deviation of 34.

Sample space n = 85,

Mean = 146

And standard deviation = 34

Then, The standard error of the sample is,

[tex]= \dfrac{\sigma}{n}\\\\= \dfrac{34}{\sqrt{85}}\\\\= \dfrac{34}{9.21}\\\\= 3.6[/tex]

Then, z-critical value for 99% is 2.58,

Margin of error = ±9.515

Confidence interval for lower bound is,

= 146 - 9.515 = 136.485

And confidence interval upper bound is,

= 146 + 9.515 = 155.515

Here, 135 is less than the lower bound,

Therefore, 135 does not lie within a 99% confidence interval.

For more details about Lower bound refer to the link given below.

https://brainly.com/question/15974739

Answer:

Answer is

the value of 135

Step-by-step explanation:

just in case some of u have different lettered answers your A may be C so i just give the numerical answer lol its easier