Respuesta :

1190335

The given equations are 3x + y - 1 = 0 and 6x + 2y - 2 = 0.

So,

Equation I = (3x + y = 1) and

Equation II = (6x + 2y = 2)

= { 2(3x + y) = 2}

= 3x + y = 2/2

= 3x + y = 1

So, The given equations are 3x + y = 1 and 3x + y = 1.

Thus, there is one equation in two variables.

So, the given equations have an infinite number of solutions.

clarch19

Answer:

1st option; 3x-y=-1

Step-by-step explanation:

-3x + y = 1

we can divide through by -1 so that the 'x' value is positive:

3x - y = -1

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