help help help help math math

Answer:
[tex]2916^3\\[/tex]
Step-by-step explanation:
As the formula is [tex]\frac{4}{3}\pi \cdot r^3[/tex]
But we take [tex]\pi[/tex] as 3 so it would be [tex]\frac{4}{3}3\cdot r^3[/tex]
And the radius is 9 half of Diameter
We would write it like this
= [tex]\frac{4}{3}3\cdot 9^3[/tex]
Then when we solve it would become [tex]2916^3\\[/tex]
I hope this helps :)