We are given –
Now put the values –
[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf x - 9y - 3x + 6y -13[/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf 9 -(9 \times -3) -(3 \times 9) +(6 \times -3) -13 [/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf 9 + 27 -27 -18 -13 [/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf 9 +\pink{\cancel{27}}-\pink{\cancel{27}} -31[/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf-22[/tex]
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Answer:
Step-by-step explanation:
In the question we have given an expression and values of x and y that is 9 and -3 respectively and ,
We have asked to find the value of x - 9y - 3x + 6y -13 by substituting values of x and y .
[tex] \longmapsto \:x - 9y - 3x + 6y -13[/tex]
So , Substituting the values of x and y ,
[tex] \longmapsto \: 9 - 9 \bold{( - 3)} - 3\bold{(9)} + 6\bold{( - 3)} - 13[/tex]
Now , calculating the values ,
[tex] \longmapsto \: 9 + 27 - 27 - 18 - 13[/tex]
[tex] \longmapsto \: 9 + \cancel{ \red{27}} - \cancel{ \red{27 }}- 18 - 13 [/tex]
[tex] \longmapsto \: 9 - 31[/tex]
[tex] \longmapsto \: \pink{\boxed{- 22}}[/tex]
