Answer:
8 years
Step-by-step explanation:
Currently
Abebe → 12 years old
Aster → 2 years
With every passing year, each of them will be 1 year older hence the difference between their ages will remain constant.
Difference in ages
= 12 -2
= 10
Let the age of Aster be x years old when Abebe is twice her age.
Abebe → 2x years old
Aster → x years old
Difference in age
= 2x -x
= x
x= 10
Aster is 10 years old when Abebe is twice her age.
Number of years passed
= 10 -2
= 8
Thus, Abebe will be twice as old as her sister in 8 years.
