- Initial velocity (u) = 0 m/s [the car was at rest]
- Distance (s) = 80 m
- Time (t) = 10 s
- Let the magnitude of acceleration be a.
- By using the equation of motion, [tex]s = ut + \frac{1}{2} a {t}^{2} [/tex]we get,[tex]80 = 0 \times 10 + \frac{1}{2} \times a \times {10}^{2} \\ = > 80 = \frac{1}{2} \times 100a \\ = > 80 = 50a \\ = > a = \frac{80}{50} \\ = > a = 1.6[/tex]
Answer:
The magnitude of its acceleration is 1.6 m/s^2.
Hope you could get an idea from here.
Doubt clarification - use comment section.
