[tex](-4.89, 3)[/tex] and [tex](4.89, 3)[/tex] are the farthest from the origin and [tex](0, -1)[/tex] is the closest from the origin.
Let be a curve of the form [tex]x^{2}+3\cdot (y-2)^{2} = 27[/tex]. The distance with respect to origin is found by using the following Pythagorean identity:
[tex]r = x^{2}+y^{2}[/tex] (1)
Where [tex]r[/tex] is the square distance function.
We can modify (1) as following:
[tex]r = [27-3\cdot (y-2)^{2}]+y^{2}[/tex]
[tex]r = 27-3\cdot (y^{2}-4\cdot y +4)+y^{2}[/tex]
[tex]r = 27-3\cdot y^{2}+12\cdot y -12 + y^{2}[/tex]
[tex]r = -2\cdot y^{2}+12\cdot y+27[/tex] (1b)
Now we apply the First and second derivative tests to determine the minimum and maximum distances from the origin:
First derivative test
[tex]-4\cdot y +12 = 0[/tex]
[tex]y = 3[/tex]
Second derivative test
[tex]r'' = -4[/tex]
The y-component represents a maximum.
Now we graph the function with the ressource of a graphing tool, we find the following points:
Farthest points: [tex](-4.89, 3)[/tex], [tex](4.89, 3)[/tex].
Closest points: [tex](0, -1)[/tex].
[tex](-4.89, 3)[/tex] and [tex](4.89, 3)[/tex] are the farthest from the origin and [tex](0, -1)[/tex] is the closest from the origin.
To learn more on ellipses, we kindly invite to check this verified question: https://brainly.com/question/19507943
