1. What is the value of x that satisfies the equation? Must show all proper work/steps!

32^2x = 16^2x+8

Student's Work

Student's Answer

A. x = 4

B. x =- 4

C. x = 16

D. x = 1

Please explain all steps

Respuesta :

[tex] {32}^{2x} = 16 ^{2x + 8} \\ = > {2}^{5(2x)} = {2}^{4(2x + 8)} \\ = > {2}^{10x} = {2}^{8x + 32} \\ = > 10x = 8x + 32 \\ = > 10x - 8x = 32 \\ = > 2x = 32 \\ = > x = \frac{32}{2} \\ = > x = 16[/tex]

Answer:

x = 16

Hope you could get an idea from here.

Doubt clarification - use comment section.