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Two airplanes leave an airport at the same time and travel in opposite directions. One plane travels 68 km/h faster than the other. If the two planes are 5052 kilometers apart after 3 hours, what is the rate of each plane?

Respuesta :

reinhard10158

Step-by-step explanation:

the slower plane travels x km in 3 hours.

the faster plane travels x + 3×68 = x + 204 km in 3 hours.

x + x + 204 = 5052 km

2x = 4848 km

x = 2424 km (in 3 hours).

so, the slower plane's speed is 808 km/h.

the faster plane's speed is 808 + 68 = 876 km/h.

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