The train will take 16 seconds to pass completely through a 300 meter tunnel.
Let suppose that the train moves itself at constant velocity, the vehicles needs to cover the tunnel length ([tex]L[/tex]) and its length ([tex]l[/tex]), both in meters, to pass through the tunnel, the time taken by the train ([tex]t[/tex]) is described by the following kinematic formula:
[tex]t = \frac{L+l}{v}[/tex] (1)
Where [tex]v[/tex] is the train velocity, in meters per second.
If we know that [tex]L = 300\,m[/tex], [tex]l = 100\,m[/tex] and [tex]v = 90\,\frac{km}{h}\,\left(25\,\frac{m}{s} \right)[/tex], then the time taken by the train is:
[tex]t = \frac{300\,m + 100\,m}{25\,\frac{m}{s} }[/tex]
[tex]t = 16\,s[/tex]
The train will take 16 seconds to pass completely through a 300 meter tunnel.
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