The probability of picking a marble that is not blue is 5/6
The proportions of the balls are given as:
[tex]Red = \frac 12[/tex]
[tex]White = \frac 13[/tex]
[tex]Blue = 6[/tex]
The probability of picking a ball that is not blue is:
[tex]P(Not\ Blue) = P(Red) + P(White)[/tex]
So, we have:
[tex]P(Not\ Blue) = \frac 12 + \frac 13[/tex]
Rewrite the fractions as equivalent fractions
[tex]P(Not\ Blue) = \frac 36 + \frac 26[/tex]
Take LCM
[tex]P(Not\ Blue) = \frac {3 + 2}6\\[/tex]
Add 3 and 2
[tex]P(Not\ Blue) = \frac {5}6[/tex]
Hence, the probability of picking a marble that is not blue is 5/6
Read more about probabilities at:
https://brainly.com/question/8652467