The number of bacterial population after 5 hours is; 816
N(t) = N_o(1 + r)^(t)
Where;
N(t) is number of bacteria after t hours
N_o is number of bacteria initially
r is growth rate
t is time
N_o = 480
r = 11.2% = 0.112
t = 5
N(5) = 480(1 + 0.112)^(5)
N(5) = 816.14
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