Respuesta :
Step-by-step explanation:
Let the athletes be 3x and 2x.
Now, By the question we get,
(3x-12)/(2x+12) = 5/4
or, 12x-48= 10x+60
or, 2x = 108
so, x = 54
now
3x= 3×54= 162
2x = 2×54=108
The number of athletes were 162 in first team and 108 in second team originally.
x is the number of athletes on first team originally ( x > 12, x ∈ Nˣ )
y ----------------------------------------second------------------( y ∈ Nˣ )
The ratio of athletes in the two teams is 3:2
⇒ [tex]\frac{x}{y} =\frac{3}{2}[/tex] (1)
After 12 athletes move from first team to second, the ratio is 5:4
⇒ [tex]\frac{x-12}{y+12} =\frac{5}{4}[/tex] (2)
(1),(2) ⇒ [tex]\left \{ {{\frac{x}{y} =\frac{3}{2}} \atop {\frac{x-12}{y+12} =\frac{5}{4}} \right. <=>\left \{ {{x=162} \atop {y=108}} \right.[/tex]
So: The first team originally has 162 numbers and the second team originally has 108 numbers
ok done. Thank to me :>