The given question can be solve using quadratic formula.
The correct option is (c) [tex]3x^2 +8x -10=-8[/tex].
Given:
The given equation is,
[tex]x=\dfrac{-8\pm\sqrt{8^2-4(3)(-1)}} {2(3)}[/tex]---------------------------(1)
Write the general quadratic equation.
[tex]ax^2 + bx +c=0[/tex]
Write the quadratic formula.
[tex]x =\dfrac {-b \pm \sqrt{(b^2 - 4ac)} } {2a}[/tex]------------------------------- (2)
Compare equation (1) and (2).
[tex]a=3\\b=8\\c=-2[/tex]
Substitute the value of [tex]a[/tex], [tex]b[/tex] and [tex]c[/tex] in general quadratic.
[tex]3x^2 +8x -2=0[/tex]
Subtract [tex]8[/tex] from each side of above equation.
[tex]3x^2 +8x -2 -8=0-8\\3x^2 +8x -10=-8[/tex]
Thus, the correct option is (c) [tex]3x^2 +8x -10=-8[/tex].
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